Description
Let's Start the code.....
1. Star Square Pattern
#include<stdio.h>
int main(){
int n;
printf("Enter the size of pattern : ");
scanf("%d", &n);
for(int i=1 ;i<=n; i++){
for(int j=1; j<=n;j++){
printf("*");
}
printf("\n");
}
return 0;
}
Output :
2. Numeric Square pattern (1)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of pattern : ");
scanf("%d", &n);
for(int i=1 ;i<=n; i++){
for(int j=1; j<=n;j++){
printf("%d ", i);
}
printf("\n");
}
return 0;
}
Output :
3. Numeric square pattern (2)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of pattern : ");
scanf("%d", &n);
for(int i=1 ;i<=n; i++){
for(int j=1; j<=n;j++){
printf("%d ", j);
}
printf("\n");
}
return 0;
}
Output :
4. Numeric Square Pattern (3)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of pattern : ");
scanf("%d", &n);
for(int i=n ;i>=1; i--){
for(int j=1; j<=n;j++){
printf("%d ", i);
}
printf("\n");
}
return 0;
}
Output :
5. Numeric Square pattern (4)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of pattern : ");
scanf("%d", &n);
for(int i=n ;i>=1; i--){
for(int j=5; j>=1;j--){
printf("%d ", j);
}
printf("\n");
}
return 0;
}
Output :
6. Numeric Square pattern (5)
#include<stdio.h>
int main(){
int n;
printf("Enter the size of patten : ");
scanf("%d", &n);
int k=1;
for(int i=1; i<=n; i++){
for(int j=1; j<=n; j++){
printf("%2d ", k);
k++;
}
printf("\n");
}
return 0;
}
Output :
7. Numeric Square pattern (6)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of patten : ");
scanf("%d", &n);
int k=1;
for(int i=1; i<=n; i++){
for(int j=1; j<=n; j++){
printf("%2d ", k);
k = k+2;
}
printf("\n");
}
return 0;
}
Output :
8. Numeric Square pattern (7)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of patten : ");
scanf("%d", &n);
int k=2;
for(int i=1; i<=n; i++){
for(int j=1; j<=n; j++){
printf("%2d ", k);
k = k+2;
}
printf("\n");
}
return 0;
}
Output :
9. Numeric Square Pattern (8)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of patten : ");
scanf("%d", &n);
for(int i=1; i<=n; i++){
for(int j=1; j<=n; j++){
printf("%2d ", i*j);
}
printf("\n");
}
return 0;
}
Output :
10. Numeric Square Pattern (9)
#include<stdio.h>
int main(){
int n;
printf("\nEnter the size of patten : ");
scanf("%d", &n);
for(int i=1; i<=n; i++){
for(int j=1; j<=(n-2); j++){
printf("%d %d ", j, i);
}
printf("\n");
}
return 0;
}