## Description

## Write a c program to check that given number is Neon or Not.

What is Neon Number?

A **neon number** is a number if the sum of the square of that number is equal to the actual number, then it is a neon number. For Example : 9 is a neon number.

Let's check 9 is really neon or not. So the square of 9 is 81.

Now the sum of square each digits 8 + 1 = 9.

So, this is neon number.

Now let's start the code...

```
#include<stdio.h>
int main(){
int n;
printf("Enter the number : ");
scanf("%d", &n);
// sqaure the given number
int sq = n * n;
// declare a variable for storing the sum
int sum = 0;
while(sq>0){
int digit = sq % 10;
sum = sum + digit;
sq = sq / 10;
}
if(n == sum){
printf("%d is Neon Number", n);
}
else{
printf("%d is Not Neon Number", n);
}
return 0;
}
```

**Output :**

Enter the number : 9

9 is Neon Number

**How it's work?**

**Step 1 : **Initilized a variable n, which store the given number by user.

**Step 2 : **Print a message for user and enhance readibility.

**Step 3 : **Take Input from user using scanf() function.

**Step 4 : **Initilized a variable sq, which store the sqaure of given number, and sum is store the addition of each digit of square.

**Step 5 : **Start while loop, and this loop is valid when the condition ( sq > 0 ) is true, then execute the loop body Repeat(Step 6).

**Step 6 : **In loop body , initilized a variable digit, this variable store the value of last digit of square, and sum = sum + digit , this is store sum of digit of sum, and remove the last digit with this piece of code ( sq = sq / 10 ), when loop not go to teminated, then the loop body executed.

**Step 7 : **Compare both given number ( n ) and sum , if sum and n is both are equal then print the given number is Neon otherwise both are not equal then print the given number is not equal.

**Algorithem Neon Number: **

- TAKE INPUT ( n )
- SET sq = n * n
- SET sum = 0
- REPEAT 5, 6, 7 while sq > 0
- SET int digit = sq % 10;
- sum = sum + digit;
- sq = sq / 10;
- CHECK ( n == sum ) then PRINT GIVEN NUMBER IS NEON NUMBER , CONDITION IS NOT TRUE GO TO STEP 9
- PRINT GIVEN NUMBER IN NOT NEON NUMBER.
- EXIT

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