## Description

A Number is a disarium number if the sum of the digits powered with their respective positions is equal to the number itself.

For Example:

89 is a Disarium Number

89:> 8+ 92 = 8 + 81 = 89

## Write a c program to check whether a given number Disarium Number.

``````#include <stdio.h>
#include<math.h>

int main()
{
int n, temp;
int sum = 0, count = 0;
printf("Enter a number : ");
scanf("%d", &n);
// First Count the digits of the number
temp = n;
while(temp!=0){
temp = temp/10;
count = count + 1;
}
temp = n;
while(count!=0){
int last_digit = temp%10;
temp = temp/10;
sum = sum + pow(last_digit,count);
count = count - 1;
}
if(sum == n){
printf("%d is a Disarium Number", n);
}else{
printf("%d is not a Disarium Number", n);
}
return 0;
}
``````

## Write a c++ program to check whether a given number Disarium Number.

``````// 175 = 1^1 + 7^2 + 5^3 = 1 + 49 + 125 = 50 + 125 = 175

#include <iostream>
#include<math.h>
using namespace std;
int main()
{
int n, temp;
int sum = 0, count = 0;
cout<<"Enter a number : ";
cin>>n;
// First Count the digits of the number
temp = n;
while(temp!=0){
temp = temp/10;
count = count + 1;
}
temp = n;
while(count!=0){
int last_digit = temp%10;
temp = temp/10;
sum = sum + pow(last_digit,count);
count = count - 1;
}
if(sum == n){
cout<<n<<" is a Disarium Number";
}else{
cout<<n<<" is not a Disarium Number";
}
return 0;
``````

Output:

Enter a Number: 175
175 is a Disarium Number.

## Algorithm to check the number is Disarium number.

• Calculate the length count digits of given number
1. SET temp = n
2. Use a while loop to check whether the number is not equal to 0.
3. Divide the number by 10 and increment the count by 1.
• SET temp = n again
• Calculate the answer of the given number
1. Use a while loop to check whether the count is not equal to 0.
2. Define and Assign last_digit
3. Calculate the last digit
4. Remove the last digit by temp = temp / 10.
5. Calculate the sum = sum + pow(last_digit, count).
6. Decrement the count by 1.
• \Check the given number and sum
1. If the given number and sum is equal then PRINT “GIVEN NUMBER IS DISARIUM” otherwise go to step 2
2. PRINT “GIVEN NUMBER IS NOT DISARIUM”;
• Exit.

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