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# Neon Number c programming language

A neon number is a number if the sum of the square of that number is equal to the actual number, then it is a neon number. For Example : 9 is a neon number.

Let's check 9 is really neon or not. So the square of 9 is 81.
Now the sum of square each digits 8 + 1 = 9.
So, 9 is neon number.

``````// Check given number in neon
#include<stdio.h>

int main(){

int n;
printf("Enter the number : ");
scanf("%d", &n);

// sqaure the given number
int sq = n * n;

// declare a variable for storing the sum
int sum = 0;

while(sq>0){
int digit = sq % 10;
sum = sum + digit;
sq = sq / 10;
}

if(n == sum){
printf("%d is Neon Number", n);
}
else{
printf("%d is Not Neon Number", n);
}

return 0;
}``````

## Algorithm to check neon number

1. TAKE input(n)
2. SET sq = n * n
3. SET sum = 0
4. REPEATE step 5, step 6, step 7 while sq > 0
5. SET int digit = sq % 10
6. sum = sum + digit
7. sq = sq / 10
8. CHECK (n == sum) then PRINT “Given number is neon number” otherwise go to step 9.
9. PRINT “Given number is not neon number”
10. EXIT
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